Ещё одна простая задачка – определение процентного содержания целевого символа в исходной строке. Пара решений:

• через стримы (примитивно, без кастомной свёртки, да и помедленней)
• и через цикл for.

Стримы

public int percentageLetter(String s, char letter) {
    long cnt = s.chars().filter(it -> it == (int) letter).count();
    return (int) (100 * cnt / s.length());
}

Success:
    Runtime:2 ms, faster than 12.22% of Java online submissions.
    Memory Usage:40.6 MB, less than 45.95% of Java online submissions.

Цикл

public int percentageLetter(String s, char letter) {
    int cnt = 0;
    for (char c : s.toCharArray()) {
        cnt += c == letter ? 1 : 0;
    }
    return 100 * cnt / s.length();
}

Success:
    Runtime:0 ms, faster than 100.00% of Java online submissions.
    Memory Usage:40.1 MB, less than 88.72% of Java online submissions.

Решение на гитхабе.

Given a string s and a character letter, return the percentage of characters in s that equal letter rounded down to the nearest whole percent.

https://leetcode.com/problems/percentage-of-letter-in-string/